7. Reverse Integer
Description
code
class Solution {
public int reverse(int x) {
int res = 0;
while (x != 0) {
int tail = x % 10;
int newNum = res * 10 + tail;
if ((newNum - tail) / 10 != res) {
return 0;
}
res = newNum;
x /= 10;
}
return res;
}
}Last updated