Product of Array Except Self
Description
Given an array nums
of n integers where n > 1, return an array output
such that output[i]
is equal to the product of all the elements of nums
except nums[i]
.
Example:
Input: [1,2,3,4]
Output: [24,12,8,6]
Constraint: It's guaranteed that the product of the elements of any prefix or suffix of the array (including the whole array) fits in a 32 bit integer.
Note: Please solve it without division and in O(n).
Follow up: Could you solve it with constant space complexity? (The output array does not count as extra space for the purpose of space complexity analysis.)
Code
class Solution {
public int[] productExceptSelf(int[] nums) {
int sum = 1;
int zeroNum = 0;
int[] output = new int[nums.length];
for (int i = 0; i < nums.length; i++) {
if (nums[i] != 0) {
sum *= nums[i];
} else {
zeroNum++;
}
}
if (zeroNum >= 2) return output;
for (int i = 0; i < nums.length; i++) {
if (zeroNum == 0) {
output[i] = sum / nums[i];
} else {
if (nums[i] == 0) output[i] = sum;
else output[i] = 0;
}
}
return output;
}
}
Last updated
Was this helpful?