Sort Array By Parity

Description

Given an array A of non-negative integers, return an array consisting of all the even elements of A, followed by all the odd elements of A.

You may return any answer array that satisfies this condition.

Example 1:

Input: [3,1,2,4]

Output: [2,4,3,1]

The outputs [4,2,3,1], [2,4,1,3], and [4,2,1,3] would also be accepted.

Note:

  • 1 <= A.length <= 5000

  • 0 <= A[i] <= 5000

Code

public int[] sortArrayByParity(int[] A) {
    int i = 0;
    int j = A.length - 1;
    int t = 0;
    while (i < j) {
        while (A[i] % 2 != 1 && i < j) {
            i++;
        }
        while (A[j] % 2 != 0 && i < j) {
            j--;
        }
        t = A[i];
        A[i] = A[j];
        A[j] = t;
        i++;
        j--;
    }
    return A;
}

Last updated

Was this helpful?